the enthalpy of the reaction form the average bond enthalpies in Table 9.4 for t
ID: 104901 • Letter: T
Question
the enthalpy of the reaction form the average bond enthalpies in Table 9.4 for the following reaction. Remember O2 has one double bond and the CaO enthalpy in co, is 799kJ/mol. (4pts) 2CM (g) + 7 Odg) 4CO2(g) + 6 H20(g) (VI) Choose one correct answer for each of the following questions. (3 pts each) 1) Which electron affinity process would liberate the most energy? A) [He] 2s2+e [He] 2s2 2pl B)[Hel 2,2 2p2 +e-[He] 2s22p3 C) [He] 2s2 2p3+e[He] 2s2 2p4 D) [He] 2s2 2p6+e [He] 252 2p6 3s1 the following two sets 2) Indicate which is larger in each of (I) Cr3+ or Cr (II) Se2 or Se A) Cr3+ is larger than Cr and Se2- is larger than Se. B) Cr3+ is larger than Cr and Se is larger than Se2- C) Cr is larger than Cr3+ and Se2-is larger than Se. D) Cr is larger than Cr3t and Se is larger than Se2- 3) O A) aluminumB) magnesium C) silicon D) sodium 4) List the elements Na, Ca, Rb, CI, He in order of decreasing first ionization energy He>CI> Ca>Na> Rb (This order indicates that He has the highest first ionization energy) le> Na> Ca>Cl> Rb e> Na> CI> Ca> Rb b>Ca>CI> Na> HeExplanation / Answer
V.
deltaH0r = 12*deltaH0b(C-H)+2*deltaH0b(C-C)+7deltaH0b(O=O)-8*deltaH0b(C=O) - 12 * deltaH0b(O-H)
deltaH0r = 12 * (423) + 2 (90.1) + 7 (498) - 8 (799) - 12 (493.4) = - 3570.6 kJ
VI.
(1)
(C)
(2) (C)
(3) (A)
(4) (A)
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