Ti(s)+2F2(g)TiF4(s) Part A 5.0 g Ti, 5.0 g F2 Express your answer using two sign

Question

Ti(s)+2F2(g)TiF4(s)

Part A

5.0 g Ti, 5.0 g F2

Express your answer using two significant figures.

6.5

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Part B

2.4 g Ti, 1.8 g F2

Express your answer using two significant figures.

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Part C

0.228 g Ti, 0.284 g F2

Express the mass in grams to three significant figures.

For the reaction

Ti(s)+2F2(g)TiF4(s)

compute the theoretical yield of the product (in grams) for each of the following initial amounts of reactants.

You may want to reference( pages 283 - 289) Section 8.5 while completing this problem.

Part A

5.0 g Ti, 5.0 g F2

Express your answer using two significant figures.

m =

6.5

  g  

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Part B

2.4 g Ti, 1.8 g F2

Express your answer using two significant figures.

m =   g  

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Part C

0.228 g Ti, 0.284 g F2

Express the mass in grams to three significant figures.

m =   g  

Explanation / Answer

part A

no of mol of Ti = 5/47.9 = 0.104 mol

no of mol of F2 = 5/38 = 0.13 mol

    Ti(s)+2F2(g) ---> TiF4(s)

   from the reaction

limiting reagent = F2

Theoreticalyield of TiF4 = n*Mwt

             = 0.13*1/2*123.86 = 8.0 g

part B

no of mol of Ti = 2.4/47.9 = 0.05 mol

no of mol of F2 = 1.8/38 = 0.047 mol

    Ti(s)+2F2(g) ---> TiF4(s)

   from the reaction

limiting reagent = F2

Theoreticalyield of TiF4 = n*Mwt

             = 0.047*1/2*123.86 = 2.9 g

part C

no of mol of Ti = 0.228/47.9 = 0.00476 mol

no of mol of F2 = 0.284/38 = 0.00747 mol

    Ti(s)+2F2(g) ---> TiF4(s)

   from the reaction

limiting reagent = F2

Theoreticalyield of TiF4 = n*Mwt

             = 0.00747*1/2*123.86 = 0.46 g

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