aluminum hydroxyde100g magnesium carbonate 105mg balanced equaton HCI(aq)+NaOH(a

Question

aluminum hydroxyde100g

magnesium carbonate 105mg

balanced equaton

HCI(aq)+NaOH(aq)----------- H2O(I)+NaCI(AQ)

CALCULATION

1- find the initial moles of HCI

2-volume of NaOH used

3-moles of NaOH USED

4-moles of HCIneutrelised by NaOH

5-moles of HCL neutrelized by the antacid

6-effectiveness of antacid = milimol HCI neutrelized / grams of antacid

which antacid is most effective?

2-

antacid1 antacid2 antacid3 antacid brand name careone live better equate regular or extra strength regular strength regular strength extra strength antacid active ingrdients calcium carbonate 500 mg calcium carbonate 500mg

aluminum hydroxyde100g

magnesium carbonate 105mg

mass of antacid 1.204g 1.259g 1.582g molarity of HCI solution 2.00M 2.00 M 2.00M volume of HCIsolution 5.00ml 5.00 ml 5.00ml molarity of NaOH SOLUTION 0.200M 0.200M 0.200M initial buret reading 0.80ml 1.24ml 2.89ml final buret reading 1.24ml 2.89ml 44.28ml

Explanation / Answer

I will do calculation for antacid 1

1)
initial moles of HCl = M(HCl) * V(HCl)
= 2.00 M * 0.005 L
= 0.01 mol

2)
volume of NaOH used = final buret reading - initial buret reading
= 1.24 mL - 0.80 mL
= 0.44 mL

3)
moles of NaOH used =M(NaOH)*V(NaOH)
= 0.200 M * 0.00044 L
=8.8*10^-5 mol

4)
moles of HCl neutralised by NaOH = 8.8*10^-5 mol

5)
moles of HCl neutralised by antacid = 0.01 mol - 8.8*10^-5 mol
= 9.912*10^-3 mol

6)
effectiveness = 9.912/1.204 = 8.23

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