1) An electric range burner weighing 669.0 grams is turned off after reaching a

Question

1) An electric range burner weighing 669.0 grams is turned off after reaching a temperature of 463.8°C, and is allowed to cool down to 22.2°C.

Calculate the specific heat of the burner if all the heat evolved from the burner is used to heat 586.0 grams of water from 22.2°C to 81.2°C.


Answer ________J/g°C

2. An electric range burner weighing 669.0 grams is turned off after reaching a temperature of 456.4°C, and is allowed to cool down to 23.9°C.

Calculate the specific heat of the burner if all the heat evolved from the burner is used to heat 579.0 grams of water from 23.9°C to 80.9°C.


Answer ________ J/g°C

Explanation / Answer

1. Heat absorbed by water = Mass of water * Specific Heat of water * Change in temp of water

Heat absorbed by water = 586.0 g * 4.184 J/g °C * (final temp of water - initial temp of water)

Heat absorbed by water = 586.0 g * 4.184 J/g °C * (81.2oC - 22.2oC) = 144657.6 J

Heat absorbed by water = Heat lost by the burner = - 144657.6 J (-ve sign indicating the loss)

Heat lost by the burner = Mass of burner * Specific Heat of burner * (final temp of burner - initial temp of burner)  

- 144657.6 J = 669.0 g * Specific Heat of burner * ( 22.2oC - 463.8oC)  

Specific Heat of burner = - 144657.6/ (669.0 * -441.6) = 0.490 J/g °C

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