Data Analysis 105 A. Calculate the total M concentration of SCN and Fe present i

ID: 1047334 • Letter: D

Question

Data Analysis 105 A. Calculate the total M concentration of SCN and Fe present in each test solution. Enter these in the table. Show the calculations for test solution #5 below. Data Table Molarity of stock KSCN solution o·0095 M Molarity of Fe(No), solution O200M Test mL. Stock mL Stock mL H20 Total added Total added Absorbance at TubeKSCN Fe(NO3)3 SCN cone (M) Fe* cone (M) 447 0.00 5.00 00 40 5.00 So 135 G.00 0o 13.00o 5.00 2.so 150 00 1o.0o 5.00 500 | 1300 ?,00 5. IS.00 0.00 O. 118 0.135 B. Considering that fact that Fe and SCN react 1:1 to form the colored ion FesCN2, what is the maximum mole/liter concentration of FeScN?* that could form in each test solution? Explain your reasoning below. (Hint: What is the limiting reagent in each solution?)

Explanation / Answer

Data Analysis:

part A)

Total SCN- =(volume of SCN-)*(molarity of stock SCN-)/total volume

Total Fe3+=(volume of Fe3+)*(molarity of stock Fe3+)/total volume

test tube 1)Total SCN- =0.0005M*(5ml/20ml)=0.000125 M

Total Fe3+=0.2M*(0.5ml/20ml)=0.005M

test tube 2)