can you please do an I.C.E chart it helps me follow the process C a Secure https

Question

can you please do an I.C.E chart it helps me follow the process

C a Secure https/edugen wileyplus.com/edugen/student/maint.uni ment CALCULATOR FULL SCREEN PRINTER VERSION BACK NEXTI STOICHIOMETRIC RELATIONSHIPS TO2/501 Unit Conversions: When a sample of NO(g) (0.02822 mol/L) is placed in 330.0 L reaction vessel at 595.0 °C and allowed to come to equilibrium the mixture contains 2.620 mol of N2(g). What is the concentration (mol/L) of O2(g)? K = C + 273 Molar Mass (g/mol NO(g) 30.01 N2(9) 28.02 O2(9) 32.00 2NO(g) N2(9)+02(9) the tolerance is +/-290 Question Attempts: 0 of 1 used SAVE FOR LATER SUBMIT ANSWE

Explanation / Answer

concentration of NO = 0.02822 M

concentration of N2 at equilibrium = 2.620 / 330 = 0.00794 M

2 NO (g)   ------------> N2 (g) +   O2 (g)

0.02822                        0               0

0.02822 - 2x                  x               x

At equilibrium :

[N2] = 0.00794 M

concentration of O2 at equilibrium = 7.940 x 10^-3 M

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