31) In electrophilic aromatic substitution reactions a bromine substituent: A) i

Question

31) In electrophilic aromatic substitution reactions a bromine substituent: A) is a deactivator and a m-director. B) is a deactivator and an o.p-director. C) is an activator and a m-director. D) is an activator and an 0.2-director. E) none of the above 32) Whichof the following is the strongest activating group in electrophilic aromatic substitution reactions? A) -CH2CH3 B)-OCH3 C)-CO2CH3 D) -NO2 E)-N(CH3)2 33) In electrophilic aromatic substitution reactions, a -NHCOCH3 substituent on the aromatic ng is: A) a deactivator and a m-director. B) a deactivator and an o.p-director. C) an activator and a m-director D) an activator and an g.-director. E) none of the above. 34) Which of the following compounds will undergo Fricdel-Crafts alkylation with (CH3)3CC AlCl3 most rapidly? A) toluene B) iodobcnzenc D) benzcocsulfonic acid 35) In electrophilic aromatic substitution reactions the hydroxyl group is an gup-director because: A) it donates electron density to the ring by induction and destabilizes the meta sigma complex. B) it donates electron density to the ring by resonance and stabilizes the orth and para sigma C) it donates electron density to the ring by induction and stabilizes the grtho and para sigma D) it donates electron density to the ring by resonance and destabilizes the meta sigma complex. E) it withdraws electron density from the ring by induction and destabilizes the meta sigma complex.

Explanation / Answer

31. Option D, Br is +M group and activate the ring towards o/p positions

32. Option E, N(CH3)2, since it is +M group donates it's lone pair of electrons towards ring

33. Option D, o/p activating group

34. Option B, iodobenzene, since Iodine is +M group and activate the ring towards substitution

35. Option B, it donates lone pair of electrons by resonance

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