Dioxane, C 4 H 8 O 2 , is a nonelectrolyte; ammonia, NH 3 , is a weak electrolyt

Question

Dioxane, C4H8O2, is a nonelectrolyte; ammonia, NH3, is a weak electrolyte; and aluminum chloride, AlCl3, is a strong electrolyte. What are the solute particles present in aqueous solutions of each compound? (Select all that apply.)

H+O2-OH -C4H7O2-C4H8O2HC4H8O2+

OH-H+NH4+O2-NH3NH4OH+

Cl3-Al+AlCl3Cl-Al3+HAlCl3+

If 0.1 mol of each compound is dissolved in solution, which one contains about 0.4 mol of solute particles, which contains 0.1 mol of solute particles, and which contains somewhere between 0.1 and 0.2 mol of solute particles?

H+O2-OH -C4H7O2-C4H8O2HC4H8O2+

OH-H+NH4+O2-NH3NH4OH+

Cl3-Al+AlCl3Cl-Al3+HAlCl3+

Explanation / Answer

The statement says that dioxane is a non electrolyte, this necessarily means that it will not dissolve so 0.1 moles of dioxane will be 0.1 moles of solute particle

AlCl3 dissociates completely, this means that

AlCl3 === Al + 3Cl

so 0.1 moles of AlCl3 will produce 0.1 moles of Al and 3 * 0.1 = 0.3 moles of Cl

0.1 + 0.3 = 0.4 moles of solute particles

Ammonia (NH3)

NH3 will dissociate partialy since it is a weak electrolyte so between 0.1 and 0.2 moles of solute particles are available.

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