.The following molecular views show reactant solutions for a precipitation react
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Question
.The following molecular views show reactant solutions for a precipitation reaction (the H20 molecules have been omitted for clarity.) 1+ 24 14 2+ 2+ 1+ Beaker A Beaker B Which of the following compounds is the REACTANT DISSOLVED in Beaker A? (1 point) a. i. Ba(NO3)2 ii. Na2O iii. Pbl2 iv. CuSO4 v. KF vi. FryP b. Which of the following compounds is DISSOLVED in Beaker B? (1 point) i. NaCI ii. Mgo ii. Fe(CI03) iv. CrPO4 v, (NH4)2CO3 vi. AlBr c. Write the molecular equation for the reaction that occurs when the 2 beakers are mixed. (Ipoint) BCE: d. When the 2 beakers are mixed, what is the precipitate that is formed? Formula Please) (1 point)Explanation / Answer
a) i). Ba(NO3)2
Cation is 2+ and anion is 1-. Thus, the possible compound in Beaker A is Ba(NO3)2 and PbI2. But PbI2 is not soluble in water.
b) v). (NH4)2CO3
Cation is 1+ and anion is 2-. Thus, the possible compound in Beaker A is (NH4)2CO3 .
c) The Balanced chemical equation
Ba(NO3)2 (aq) + (NH4)2CO3 (aq) --> BaCO3(s) + 2NH4NO3 (aq)
d) The formed precipitate is BaCO3
e)
Total Ionic Equation (TIE)
Ba2+(aq) + 2NO3- (aq) + 2NH4+(aq) + CO32- (aq) --> BaCO3(s) + 2NH4+(aq) + 2NO3- (aq)
Net Ionic Equation (NIE)
Ba2+(aq) + CO32- (aq) --> BaCO3(s)
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