need to find “percentage of salicylic acid impurity” - absorbance (y) = 0.222 De
ID: 1045474 • Letter: N
Question
need to find “percentage of salicylic acid impurity”
- absorbance (y) = 0.222
Determination of Salicylate via Reaction with Fe(lIl) 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 0 20 40 60 80 Concentration (mM) Figure 1, Calibration plot of Absorbance vs Concentration of Feil)-salicylate complex. Steps: Use this graph and the equation; to calculate the concentration of the complex for which you measured the absorbance. (y absorbance, solve for x) 2. x you calculated from step 1 is the concentration of the complex formed. It is formed via a 1:1 reaction between the salicylic acid impurity in your aspirin and the Fe(NOsh added. Units are mM 3. From the mM concentration, you calculate the millimoles (multiply by the volume in L) and then the moles of salicylic acid and then the grams of salicylic acid. That is the amount of impurity of salicylic acid present in your aspirin. 4. (mass of Salicylic acid/mass of aspirinlX100 gives the % impurity.Explanation / Answer
From the above data,
Percentage of salicylic acid impurity =
Mass of Salicylic acid / Mass of aspirin * 100
From above data, Mass of salicylic acid = 2g
Mass of aspirin=1.71g
%age of salicylic acid = 2/1.71*100= 116.95
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