14 April Dibenzyl Ketone Report Question 3 Not yet answered Marked out of 1.0000
ID: 1044930 • Letter: 1
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14 April Dibenzyl Ketone Report Question 3 Not yet answered Marked out of 1.00000 With the advent of photosynthesis, the amount of oxygen in the atmosphere has varied over the eons up to 35 % by volume, theoretically leading to larger plants and animals. The current concentration is 21 % oxygen, 78 % nitrogen, and 1 % other gases such as argon and carbon dioxide. Assuming an atmosphere of 32 % oxygen, to the nearest whole number (no decimal) what would be the ideal volume of water (in mL) initially placed in a 25 mL graduated cylinder (assuming the graduation goes up to the lip of the container) fo optimal combustion (biggest explosion) if we collected pure hydrogen by displacement as in this experiment? Make suret account for the stoichiometry of the combustion, that all gases involved are diatomic, and that equal moles of different idea gases occupy equal volumes at the same temperature. Flag question Answe Previous page Next Dibenzyl Ketone Quiz Jump to... TetraphenylcyclopentadienoneExplanation / Answer
Dibenzyl molecular weight = 210.28 g/mole Formula = C15H14O, Phenylaceticacid M.wt 136.15, Formula = C8H8O2
Weight of dibenzyl ketone prepared after reaction = 0.865 g
Number moles of dibenzyl ketone formed after reaction = 0.00411
2 Phenylaceticacid ----------------> 1 Dibenzylketone
Since it is a 2 : 1 mole ration reaction.
So, number of moles of dibenzylketone = 2*moles of phenylaceticacid
Number of moles of phenylaceticcaid reacted = 0.00822
Weight of Phenylacetic acid = 0.00822*136.15 = 1.12 g
%Yield = (Actual Yield/Theoretical Yield)*1000
19 = (0.865/Theoretical Yield)*100
Theoretical Yield = (0.865/19)*100 = 4.55 g
Number of moles of Phenylaceticacid required to get %Yield 19 = (4.55/210.28)*2 = 0.08655
Weight of Phenylaceticacid = 0.08655*136.15 = 11.78 g
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