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ALEKS Sharon Quijandria - Learn Do Critical the Helpers Apple Google Maps YouTube News? Popular Google O ADVANCED MATERIAL Using a rate law The rate of a certain reaction is given by the following rate law: rate = k | N,110 Use this information to answer the questions below. What is the reaction order in N2? What is the reaction order in 03? What is overall reaction order? At a certain concentration of N2 and O3, the initial rate of reaction is 9.0 x 104 M/s. What would the initial rate of the reaction be if the concentration of N2 were doubled? Be sure your answer has the correct number of significant digits The rate of the reaction is measured to be 78.0 M s when [N2]-1.5 M and [O3] 0.87 M. Calculate the value of the rate constant. Be sure your answer has the correct number of significant digits Explanation Check 13

Explanation / Answer

Ans. #1. Order of reaction in N2 = 3

#2. Order of reaction in O3 = 1

#3. Overall order of reaction = Order of reaction in N2 + Order of reaction in O3

                                                = 3 + 1 = 4

#4. Let the [N2] in initial experiment is X.

Given,

            Rate for initial experiment, r1 = k [X]3 [O3] = 9.0 x 104 M s-1

# IN second experiment, [N2] is doubled. So, [N2] = 2. Calculate new rate while keeping all other values the same-

            Rate for initial experiment, r2 = k [2X]3 [O3] = k 8 [X]3 [O3]

# Dividing r2 / r1      -

            r2 / r1 = (k 8 [X]3 [O3]) / (k [X]3 [O3]) = 8

            Or, r2 = 8 x r1 = 8 x (9.0 x 104 M s-1) = 7.2 x 105 M s-1

# So, the new rate is:           7.2 x 105 M s-1

#5. Putting the values in rate law equation-

            r = 78.0 M s-1 = k (1.5 M)3 (0.87)

            Or, k = 78.0 M s-1 / (2.93625 M4)

            Hence, k = 26.6 M-3 s-1

Therefore, rate constant, k = 26.6 M-3 s-1

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