4/29/2018 11:55 PM 6.6/10 Gradebook Calculator Periodic Table Question 17 of 22

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4/29/2018 11:55 PM 6.6/10 Gradebook Calculator Periodic Table Question 17 of 22 Map Sapling Learning macmilan learning vehicle airbag uses a gas generator that contains a mixture of three compounds: NaN3, KNO3, and Sio A series of three reactions is used to convert the highly toxic sodium azide, NaN3, into N2 gas and harmless silicate glass. The nitrogen gas fills up the airbag, causing it to rapidly expand in a head-on collision Balance the reactions involved in the deployment of an airbag by inserting the appropriate coefficients 1. NaN, s) -> Nals)+ N.Ug) 2. Nas) + KNO K,O,Sis+Na,O,Si The drive-side airbag deploys when a sports car is in a head-on collision. The airbag inflates to a volume of 62.3 L and a pressure of 1.91 atm at 25.0 C. Calculate the amount of NaN3 in grams, that the manufacturer of the vehicle placed into the gas generator to produce this amount of nit gas behaves as an ideal gas and the only source of the nitrogen gas is the first reaction shown above. A list of physical constants can be found here n gas. Assume the nitrogen Number Previous O Check Answer Next Exit Hint

Explanation / Answer

i)

1) 2NaN3(s) - - - - - - > 2Na(s) + 3N2(g)

2) 10Na(s) + 2KNO3(s) - - - - > K2O(s) + 5Na2O(s) + N2(g)

3)K2O(s) + Na2O(s) + 2SiO2(s) - - - > K2O3Si(s) + Na2O3Si(s)

ii)

2NaN3(s) - - - - - - > 2Na(s) + 3N2(s)

Stoichiometrically, 3 moles of N2 produced from 2moles of NaN3

Ideal gas equation is

PV = nRT

n = PV/RT

n = 1.91atm × 62.3L / 0.082057(L atm /mol K) × 298.15K

n = 4.8637

therefore,

no of N2 gas produced = 4.8637

4.8637moles of N2 comes from (2/3)×4.8637 = 3.2425 moles of N2

Molar mass of NaN3 = 65.0099

Mass of NaN3 = 3.2425mol× 65.0099g/mol = 210.79g

Therefore,

mass of NaN3 in air bag =210.79g

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