1.a 50.0 ml sample of a 6.0m solution of hcl is diluted to 200 ml. What is the n
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Question
1.a 50.0 ml sample of a 6.0m solution of hcl is diluted to 200 ml. What is the new concentration. 2.what is the final concentration prepared by adding water to a 50.0 ml of 1.5 m naoh to make 1.00l of solution 3.a 50 ml sample of 12M solution of Hcl is diluted to 250ml. What is the new concentration. 1.a 50.0 ml sample of a 6.0m solution of hcl is diluted to 200 ml. What is the new concentration. 2.what is the final concentration prepared by adding water to a 50.0 ml of 1.5 m naoh to make 1.00l of solution 3.a 50 ml sample of 12M solution of Hcl is diluted to 250ml. What is the new concentration. 1.a 50.0 ml sample of a 6.0m solution of hcl is diluted to 200 ml. What is the new concentration. 2.what is the final concentration prepared by adding water to a 50.0 ml of 1.5 m naoh to make 1.00l of solution 3.a 50 ml sample of 12M solution of Hcl is diluted to 250ml. What is the new concentration.Explanation / Answer
1) M1 concentration of HCl = No. of moles of HCl/vol in lts = 6/0.05 = 120
V2 vol of solvent = 200 ml
M2 = ? M1V1 = M2V2 120X50 = M X 200
M = 6000/200 = 30 M = New concentration of HCl
2) M1 Molarity of NaOH = No. of moles/vol in lts = 1.5/0.05 = 30
V2 Vol of water = 1lt = 1000ml
M2 new molarity of NaOH = ?
M1V1 = M2V2
30X50 = MX1000
M = 1.5 = Final concentration of NaOH
3) M1 Molarity of HCl = 12M
V1 = 50 ml
V2 = 250ml
M1V1 = M2V2
12x50 = Mx250
M= 2.4 = new concentration
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