92. Ql: 24: Name (CAPS) Q5. Date:- Q1. What is the pll of a 0.29 M solution of m
ID: 1044530 • Letter: 9
Question
92. Ql: 24: Name (CAPS) Q5. Date:- Q1. What is the pll of a 0.29 M solution of maethylamine (CH NHa, 410-) t 25 C Q2. The rate constant for a first-order reaction is 1.8 x 103 s at 692 K and 3.9 X 102 gl at 874 K. What is the activation energy? (R-8314 J/Kmol) Q3. The following reaction is investigated (assume an ideal gas mixture): Initially there are 0.10 mol of NO and 0.25 mol of NJH, in a 10.0-L container. If there are 0.056 mol of N:O at equilibcium, how many moles of Nz are present at equilibrium?Explanation / Answer
CH3NH2 + H2O ---------------> CH3NH3^+ (aq) + OH^- (aq)
I 0.29 0 0
C -x +x +x
E 0.29-x +x +x
Kb = [CH3NH3^+][OH^-]/[CH3NH2]
4.4*10^-4 = x*x/0.29-x
4.4*10^-4 *(0.29-x) = x^2
x = 0.011
[OH^-] = x = 0.011M
POH = -log[OH^-]
= -log0.011
= 1.9586
PH = 14-POH
= 14-1.9586 = 12.0414
2.
K1 = 1.8*10^-2 sec^-1
T1 = 692K
K2 = 3.9*10^-2sec^-1
T2 = 874K
logK2/K1 = Ea/2.303*R [ 1/T1 -1/T2]
log3.9*10^-2/1.8*10^-2 = Ea/2.303*8.314 [ 1/692 - 1/874]
0.3357 = Ea(0.00144-0.00114)/19.147
Ea = 0.3357*19.147/0.0003 = 21426J/mole = 21.426KJ/mole
3.
2N2O + N2H4 -------------------> 3N2 + 2H2O
I 0.1 0.25 0 0
C -2*0.022 -0.022 3*0.022 2*0.022
E 0.056 0.228 0.066 0.044
[N2] = 0.066mole at equilibrium
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