Question 5 (1 point) What is/are the unit factor(s) required to convert volume o

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Question 5 (1 point)

What is/are the unit factor(s) required to convert volume of a pure substance in L to moles of the substance using unit analysis?

Question 5 options:

×1 mL1000 L1mL1000L×gmLgmL×molgmolg

×1 L1000 mL1L1000mL×mLgmLg×gmolgmol

×1000 mL1 L1000mL1L×mLgmLg×gmolgmol

×1000 mL1 L1000mL1L×gmLgmL×molgmolg

×1000 L1 mL1000L1mL×mLgmLg×gmolgmol

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Question 6 (6 points)

One mole of ethanol generates 1235.4 kJ of energy through combustion and one mole of octane generates 5074.1 kJ of energy through combustion. The molar masses and densities of these two fuels are given in the table below. Using the information given in the table, apply unit analysis to calculate the amount of energy produced by burning one gram of each of the two fuels, the amount of energy produced by burning one liter of each of the two fuels, and the moles of each fuel per liter of fuel. Choose the best numerical answer for (a) through (e) to complete the table.

Question 6 options:

(e) moles of ethanol in one liter of ethanol

(c) energy produced by burning one liter of ethanol

(f) moles of octane in one liter of octane

(b) energy produced by burning one gram of octane

(d) energy produced by burning one liter of octane

(a) energy produced by burning one gram of ethanol

6.12

17.0

26.82

36.1

44.42

79.8

1235.4

5074.1

2.11×104

3.10×104

3.41×104

5.69×104

6.35×104

5.80×105

×1 mL1000 L1mL1000L×gmLgmL×molgmolg

×1 L1000 mL1L1000mL×mLgmLg×gmolgmol

×1000 mL1 L1000mL1L×mLgmLg×gmolgmol

×1000 mL1 L1000mL1L×gmLgmL×molgmolg

×1000 L1 mL1000L1mL×mLgmLg×gmolgmol

Explanation / Answer

5) We wish to convert volume of the substance (in L) to mole(s) of the substance. Do the following conversions step by step.

Volume in mL = (L)*(1000 mL/1 L)

Mass in grams = (L)*(1000 mL/1 L)*(g/mL)

Moles = (L)*(1000 mL/1 L)*(g/mL)*(mol/g)

The unit analysis is (L)*(1000 mL/1 L)*(g/mL)*(mol/g) (ans).

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