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Exercises Complete the table below Find the % of Cin Co, Find the % of H in H2O

ID: 1043922 • Letter: E

Question

Exercises Complete the table below Find the % of Cin Co, Find the % of H in H2O Find the % of Zn in Znco, Find the % of Mg in MgCl2 Find the % of Pb in PbO, Find the % of Clin MgCh Find the % of Pb in Pbyo, PERCENTAGE YIELD. When a substance is made by a chemical reaction, you do not always get as much as you expected. This can be for a number of reasons: 1) Some of the material is lost in the experimental process. 2) An unwanted reaction takes place, giving you less of your product 3) The reaction is reversible. The percentage yield compares the mass you actually get with the amount you expected to ge under ideal conditions Percentage Yield-Mass obtained in Experiment x 100 Expected Mass e.g. Ebenezer expects to get 4.6g of alcohol from his experiment. The actual mass obtained was 3.5g. Find the % yield. Answer=32 x 100 = 76.1% Priscilla is making some exclusive perfume. She expects to get a maximum of 10.Gg from her procedure, but only manages to get 7.1g. What is her percentage yield? Answer-2L x 100-6796 4.6

Explanation / Answer

Percent of C in CO2

Molar mass of CO2=12.01+(16x2)=44.01

Therefore % of C in CO2 = (12.01/44.01) x 100%=27.29%

Percent of H in H2O

Molar mass of H2O= (1.008x2)+16 = 18.016

Therefore % of H in H2O = (2.016/ 18.016)x 100%=11.19%

Percent of Zn in ZnCO3

Molar mass of ZnCO3= 65.38+12.01+(16x3)= 125.39

Therefore % of Zn in ZnCO3=(65.38/125.39)x 100%=52.14%

Percent of Mg in MgCl2

Molar mass of MgCl2=24.3+(35.45x2)=95.2

Therefore % of Mg in MgCl2=(24.3/95.2) x 100%=25.52%

Percent of Pb in PbO2

Molar mass of PbO2= 207.2+(16x2)=239.2

Therefore % of Pb in PbO2=(207.2/239.2) x 100%=86.62%

Percent of Cl in MgCl2

Molar mass of MgCl2=95.2

Therefore % of Cl in MgCl2=(70.9/95.2) x 100%=74.47%

Percent of Pb in Pb2O3

Molar mass of Pb2O3=(207.2x2)+(16x3)=462.4

Therefore % of Pb in Pb2O3=(207.2/462.4) x 100%=44.81%

Percent of C in CO2

Molar mass of CO2=12.01+(16x2)=44.01

Therefore % of C in CO2 = (12.01/44.01) x 100%=27.29%

Percent of H in H2O

Molar mass of H2O= (1.008x2)+16 = 18.016

Therefore % of H in H2O = (2.016/ 18.016)x 100%=11.19%

Percent of Zn in ZnCO3

Molar mass of ZnCO3= 65.38+12.01+(16x3)= 125.39

Therefore % of Zn in ZnCO3=(65.38/125.39)x 100%=52.14%

Percent of Mg in MgCl2

Molar mass of MgCl2=24.3+(35.45x2)=95.2

Therefore % of Mg in MgCl2=(24.3/95.2) x 100%=25.52%

Percent of Pb in PbO2

Molar mass of PbO2= 207.2+(16x2)=239.2

Therefore % of Pb in PbO2=(207.2/239.2) x 100%=86.62%

Percent of Cl in MgCl2

Molar mass of MgCl2=95.2

Therefore % of Cl in MgCl2=(70.9/95.2) x 100%=74.47%

Percent of Pb in Pb2O3

Molar mass of Pb2O3=(207.2x2)+(16x3)=462.4

Therefore % of Pb in Pb2O3=(207.2/462.4) x 100%=44.81%

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