I\'m having trouble making the graph for this. My assumption is that the percent

Question

I'm having trouble making the graph for this. My assumption is that the percent remaining for t-butyl chloride are: 80, 85, 90, 95. However, when I do use those concentrations, I don't get a nice curve like I would expect, nor do I get a straight slope when I do the natural log of those. Honestly, I get the same graph for both. What am I doing wrong?

Table 3105-9: Time Trials for S1 Reactions %t-BuCl | Time | Temp | Ti Exp. solution solution Water completion remaining Trial1 Trial Tria t-BuCINaOH 2 (sec) C) (sec( C) (mL) (mL) (mL) 3.00 0.60 6.40 20 b 3.00 0.45 6.55 c 3.00 0.30 6.70 d 3.00 0.156.85 80 5:35 21 1:30 | 29 | 15 1 0 28 2 Analysis. Plot your data for Experiments a-d as ln(% t-butyl chloride remaining) vs. time. A straight line indicates that our proposed equation for a first order reaction is correct. The slope of this line is-k, where k is the rate constant. Determine k, remembering that slope (y2-y) / (x2-x)

Explanation / Answer

i also tried to plot the graph. but check the first value 5:35 minute is right or not.

Then plot ln (% of t-butyl chloride ) vs time in seconds

slope from plot = -1748.99 from Y = mx+ c

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.