Name. Date Section... POTENTIOMETRIC TITRATIONS HOMEWORK 1. Complete the followi
ID: 1043741 • Letter: N
Question
Name. Date Section... POTENTIOMETRIC TITRATIONS HOMEWORK 1. Complete the following table. Using the information therein, identify your unknown acid. Acid: Molecular Weight 204.2 g/ma 13616qa/mo? 6. 072 gImol 36.034 gimol 19212 9 imol Potassium hydrogen CHsKO phthalate Potassium hydrogen KHS0 sulphate Maleic Acid Potassium dihydrogen KH2 PO4 H+04 phosphate CCHEO Citric Acid 2. Determine the percent error for your molecular weight as compared to the known values given inpart one above. Determine the percent error foryour acid dissociation constant (Ka) as compared to the known values given inpart one above. 3. 4. On your printed graph, clearly specify the location of the equivalence point. Shown the tangent lines used to approximate the location or plot the first derivative used to locate the equivalence point.Explanation / Answer
2. The given molecular weight of C8H5KO4 = 204.2 g/mol
The actual molecular weight of C8H5KO4 = (8*12)+(5*1)+(1*39.1)+(4*16) = 204.1 g/mol
The % error in the molecular weight of C8H5KO4 = {(204.2-204.1)/204.2}*100 = 0.05%
The given molecular weight of KHSO4 = 136.169 g/mol
The actual molecular weight of KHSO4 = (1*39.1)+(1*1)+(1*32)+(4*16) = 136.1 g/mol
The % error in the molecular weight of KHSO4 = {(136.169-136.1)/136.169}*100 = 0.05%
The given molecular weight of C4H4O4 = 116.072 g/mol
The actual molecular weight of C4H4O4 = (4*12)+(4*1)+(4*16)11 = 116 g/mol
The % error in the molecular weight of C4H4O4 = {(116.072-116)/116.072}*100 = 0.06%
The given molecular weight of KH2PO4 = 136.084 g/mol
The actual molecular weight of KH2PO4 = (1*39.1)+(2*1)+(1*31)+(4*16) = 136.1 g/mol
The % error in the molecular weight of KH2PO4 = {(136.1-136.084)/136.084}*100 = 0.01%
The given molecular weight of C6H8O7 = 192.12 g/mol
The actual molecular weight of C6H8O7 = (6*12)+(8*1)+(7*16) = 192 g/mol
The % error in the molecular weight of KHSO4 = {(192.12-192)/192.12}*100 = 0.06%
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