11. For the reaction: 2A+B-products, write the rate expression for this reaction

Question

11. For the reaction: 2A+B-products, write the rate expression for this reaction and the rate constant with proper units given the following data: Initial Rate M A. 0.10 0.30 0.20 0.30 0.10 0.10 0.10 0.20 0.30 2.0 x10-2 8.0 x 102 1.8 x 10 8.0 x 102 1.8 x 10-1 12. The following data are obtained for the initial rates of reaction in the reaction: A+2B+C-2D + E AL.M 1.4 0.70 0.70 1.40 0.70 Experiment BI.M 1.4 1.40 0.70 1.40 0.70 C.MInitial rate 1.00 1.00 1.00 0.50 0.50 Ri R5 A. What is the order of reaction with respect to A and B B. The order with respect to C is-1. What is the overall order of the reaction?

Explanation / Answer

11.

General rate law expression is,

Rate = k[A]m[B]n

Do, (1) / (2)

2.0 * 10-2 / ( 8.0 * 10-2 ) = (0.10 / 0.20)m

(0.25) = (0.5)m

(0.5)2 = (0.5)m

So, m = 2 and order with respect to A = 2

Now do (2) / (4)

8.0 * 10-2 / ( ( 8.0 * 10-2 ) = ( 0.10 / 0.20 )n

1 = (0.5)n

(0.5)0 = (0.5)n

SO, n = 0 and order with respect to B = 0

Over all order of reaction = 2 + 0 = 2

Rate .law,

Rate = k[A]2

(1) =>

2.0 * 10-2 = k(0.10)2

k = 2.00 M-2.s-1 (Or) 2.00 L2/mol2.s

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