Kitzmiller-Sp CHM113 iodide react with chlorine 9 Determine the liters of iodine
ID: 1043307 • Letter: K
Question
Kitzmiller-Sp CHM113 iodide react with chlorine 9 Determine the liters of iodine gas produced if 9.70 moles of potassium gas at STP according to the following balanced equation: a) 62.7L b) 125L c) 175 L d) 109 L Tire manufacturers recommend measuring tire pressure when the car has not been driven. The volume and number of molecules of gas remain constant. When the tire pressure is measured on a hot day a) there is a decrease in the number of collisions between gas molecules molecules b) there is an increase in the number of collisions between gas c) the average kinetic energy increases d) the average kinetic energy stays the same The total pressure of a mixture of gases (O, Hs, He) in a container is 7.0 atm. Determine the partial pressure of O; in the container if the partial pressures of H and He are 2.8 atm and 0.9 atm, respectively a) 3.3 atm b) 3.7 atm c) 7.0 atm d) 10.7 atm Determine the partial pressure of O2 in a vessel containing 9.20 mole O, 4.55 mole H2, and 3.57 mole He if the vessel has a total pressure of 0.988 atm. 12· a) 0.525 atm b) 0.509 atm c) 0.498 atm d) 0.488 atm 13. A 4.0 L tank containing a gas at 8.0 atm and a 12.0 L tank containing a gas at 9.0 atm is separated by a valve. Calculate the final pressure in the tanks when the valve is opened. Assume temperature remains constant. a) 4.3 atm b) 5.8 atm c) 7.3 atm d) 8.8 atm 4 L 8 atm 12 L 9 atm
Explanation / Answer
9. The reaction in question is 2KI (aq) + Cl2 (g) --------> 2KCl (aq) + I2 (g)
Given: 9.70 moles of KI reacts with Chlorine gas.
To find out: Litres of Iodine produced when 9.70 moles of KI reacts at STP
At STP, 1 mole of gas occupies 22.4 L of gas.
Volume of I2 produced = 9.70 moles KI * ( 1mole of I2 / 2 moles KI) * (22.4 Litres I2 / 1mole of I2)
Volume of I2 produced = 108.64 L = 109 L
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