Use Part A to answer questions below. Please show your calculations. Experiment

ID: 1042259 • Letter: U

Question

Use Part A to answer questions below. Please show your calculations.

Experiment 25 Report Sheet Calorimetry Lab Sec Name Date A. Specific Heat of a Metal Unknown No. Desk No. Trial 1 Trial 2 15002 22,791 1. Mass of metal (g) 2. Temperature of metal (boiling water) ( C) 3. Mass of calorimeter (g) 4. Mass of calorimeter +water (g) 5. Mass of water (g) 6. Temperature of water in calorimeter (C) 7. Maximum temperature of metal and water frem-graptrC) 8. Instructor's approval of graph 9.13a 43 2 20 24.50 3?.sa 34.5 Calculations for Specific Heat of a Metal 1. Temperature change of water, AT (C) 2. Heat gained by water (J) 3. Temperature change of metal, ATCC) 4. Specific heat of metal, equation 25.5 g C) 5. Average specific heat of metal (Ug ."O Data Analysi *Show calculations for Trial 1 using the correct number of significant figures.

Explanation / Answer

Trail 1

Trail 2

1. Temperature change of water, ?T (°C) = (maximum temperature of metal and water) – (temperature of water in calorimeter)

30.52 – 23.50 = 7.02

34.51 – 24.50 = 10.01

2. Heat gained by water (J) = (mass of water)*(specific heat of water)*(temperature change of water)

Specific heat of water = 4.184 J/g.°C

(20 g)*(4.184 J/g.°C)*(7.02 °C) = 587.4336 J

(20 g)*(4.184 J/g.°C)*(10.01 °C) = 837.6368 J

3. Temperature change of metal, ?T (°C) = (temperature of metal) – (maximum temperature of metal and water)

100 – 30.52 = 69.48

100 – 34.51 = 65.49

4. Specific heat of metal (J/g.°C) (see calculation below for trial 1)

0.5636

0.5610

5. Average specific heat of metal (J/g.°C)

½*(0.5636 + 0.5610) = 0.5623 ? 0.563

Calculation:

Let S be the specific heat of the metal. We can write,

Heat lost by the metal = (mass of metal)*(specific heat of metal)*(temperature change of metal) = (15.002 g)*S*(69.48 °C) = 1042.3390S g.°C.

As per the principle of thermochemistry,

Heat lost by metal = Heat gained by water

====> 1042.3390S g.°C = 587.4336 J

====> S = 0.5636 J/g.°C.