6.00g of oxalic acid (C204H2) is dissolved in 150.0 mL distilled water to make s

Question

6.00g of oxalic acid (C204H2) is dissolved in 150.0 mL distilled water to make standard acid solution. This acid solution is used to titrate an unknown KOH solution. At the end point, 12.5 mL of unknown KOH solution is use to titrate 25.0 mL of the oxalic acid. calculate the concentration (Molarity) of oxalic acid solution(A:0.444M) a. b. Calculate the molarity of unknown KOH solution (A:1.77M) 13. 25.00 mL NaOH is used to titration 15.00 mL of 0.175 M HCI. Write a balanced reaction equation Calculate the concentration of NaOH (A: 0.105M) a. b.

Explanation / Answer

12. A. Molarity (M) = mass of solute x1000/Molar mass of solute x volume of solvent

Molarity of Oxalic acid = 6x1000/90x 150

M= 0.444 M

B. A/C to Dilution principle MaVa = MbVb

Mb = MaVa /Vb

Mb = 0.444x 25/12.5

Mb = 0.888 M per one mole of KOH

Mb = 0.888x 2 = 1.77 M per 2 moles of KOH

13. A. NaOH(s) + HCl (aq) = NaCl (aq) + H2O (l)

B. A/c to Dilution principle MaVa =MbVb

Mb = MaVa /Vb

Mb = 0.175x 15/25

Mb = 0.105 M

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