Practice With Calorimetry And Heat 75.0 g of cast iron was heated to 100°C and t

Question

Practice With Calorimetry And Heat 75.0 g of cast iron was heated to 100°C and then plunged into 100 g of water at 23.0°C. Calculate the final temperature. Cast iron has specific heat of 0.46 JigC. 2. A 25.0 g sample of an unknown metal at 99.5°C is placed into a calorimeter holding 50.0 g of water at 22.3°c. The final temperature was 26.2C; what was the specific heat of the metal? 3. 30.0 g of water at 7.00°C is mixed with 50.0 g of water at 57.0°C. Calculate the final mixture assuming no heat is lost to the surroundings. temperature of the

Explanation / Answer

Question 1

Q = mc?T

Q = heat energy (Joules, J), m = mass of a substance (kg)

c = specific heat (units J/kg?K), ? is a symbol meaning "the change in"

?T = change in temperature (Kelvins, K)

Heat lost by cast ion= Heat gained by water

75 x 0.46 x (100 - Tf ) = 100 x 4.184 x (Tf - 23)

3450 - 34.5 Tf = 418.4 Tf - 9623.2

452.9 Tf = 13073.2

Tf = 28.86 Deg Cel

Hence final temperature of mixture is 28.86 Deg Cel

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