B. What is the molecular weight, density, mass, and mole required to give 5 mL o

Question

B. What is the molecular weight, density, mass, and mole required to give 5 mL of methanol? C. What is the molecular weight and mass required to give 0.007 mole of salicylic acid? B. What is the molecular weight, density, mass, and mole required to give 5 mL of methanol? C. What is the molecular weight and mass required to give 0.007 mole of salicylic acid? B. What is the molecular weight, density, mass, and mole required to give 5 mL of methanol? C. What is the molecular weight and mass required to give 0.007 mole of salicylic acid?

Explanation / Answer

Answer b-

Molecular weight of methanol(CH4O) = 12+4+16= 32 g/mol

Density of pure methanol =792 kg/lit. ( at rt)

Thuse 1 liter methanol weighs =792kg

5ml=0.005lit =3.96 gm methanol

Now by defination ,

Mole= weight÷ molecular weight

3.96÷32 = 0.124 mole/5 ml of methanol

Answer. C

Molecular weight of salicylic acid (C6H4(OH)COOH)

= (12×6) +4+17+12+(16×2)+1

= 138 g/mol

Now see , 1mole of salicylic acid =138 g

0.007 mole contained in 138×0.007 = 0.966 gm of salicylic acid.

Thuse when 0.966 g of salicylic acid dissolved in 1 lit solvent will give 0.007 molar solution

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