dApr 11 AM COt is alowed with a one time 10%penalty to submitted score. Use the
ID: 1041486 • Letter: D
Question
dApr 11 AM COt is alowed with a one time 10%penalty to submitted score. Use the Refeseaces to access importaat valees if needed for tis rti Balanco the reaction between 112PC, and NO?to form itros, and NO2 in basic solution when you have balanced the eqiation using the smallest integers possible, enter the coefficients of the species shown. 11 PO Water appears in the balanced equation as a (reactant, product, neither) with a coefficient of (Enter 0 for neither.) How mamy electross are transferred in this reaction? Autosaved at 3 01 PrtScnExplanation / Answer
1. Separate the redox reaction into oxidation half and reduction half reactions.
Oxidation half reaction Reduction half reaction
H2PO2- ----------> HPO32- NO3- ----------> NO2-
2. Balance all atoms other than O and H
H2PO2- ----------> HPO32- NO3- ----------> NO2-
3. To balance oxygen atoms in basic medium add OH- ions.
H2PO2- + OH- ----------> HPO32- NO3- ----------> NO2- + OH-
4. To balance hydrogens in basic medium add H2O molecules.
H2PO2- + OH- ----------> HPO32-+ 2 H2O NO3- + H2O ----------> NO2- + OH-
5. Repeat (3) and (4) steps till all O and H get balanced.
H2PO2- + 3 OH- ----------> HPO32-+ 2 H2O NO3- + H2O ----------> NO2- + 2 OH-
6. To balance charges add electrons at more positive charge side.
H2PO2- + 3 OH- ----------> HPO32-+ 2 H2O + 2 e- NO3- + H2O + 2 e- ----------> NO2- + 2 OH-
7. To equalise electrons in both the half reactions , do, OHR * 1 and RHR * 1
H2PO2- + 3 OH- ----------> HPO32-+ 2 H2O + 2 e- NO3- + H2O + 2 e- ----------> NO2- + 2 OH-
8. Now add the balanced half reactions to get balanced redox reaction.
H2PO2- + 3 OH- ----------> HPO32-+ 2 H2O + 2 e-
NO3- + H2O + 2 e- ----------> NO2- + 2 OH-
--------------------------------------------------------------------------
H2PO2- + NO3- + OH- ----------> HPO32- + NO2- + H2O
--------------------------------------------------------------------------
Verify Left Right
P 1 1
N 1 1
O 6 6
H 3 3
Charge -3 -3
Hence the redox reaction is balanced.
Now,
The water molecules will appear at products side with coefficient 1.
The number ofelectrons transferred = 2
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