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xe@chegg Study l Guided S Files × ? ? C Secure ! https://canvas.hawkeyecollege.edu/courses/16860/files/folder/Take% HMy Hawkeye! Log in 001%20Exams?preview 964334 : Apps O canvas pOutlook.com-Micr Google Docs e chegg Study N Netflix a Amazon ? Google Calendar CHM-122-E3TH.docx Download load ?Info ×Close Page of 2 1. (5) Solid Fe reacts with aqueous sulfuric acid (H2SO4) to form aqueous iron (IIl) sulfate and hydrogen gas. Write out and balance the chemical equation, including phases. Dashbo 2. (5) What type of reaction is this? Can it undergo redox? If so, write out the balanced half reactions. 3. (10) You have 25.3 g of Fe and 65.8 g of H2S04; which reactant is limiting for the production of hydrogen gas, and how much hydrogen gas will this produce?Explanation / Answer
1) 2 Fe(s) + 3 H2SO4(aq) --------------- Fe2(SO4)3 + 3 H2(g)
2)This is single displace ment reaction.
2 Fe(s) + 3 H2SO4(aq) --------------- Fe2(SO4)3 + 3 H2(g)
0 +1 +3 0
So ,It is redox reaction
Fe undergoes oxdiation and H2 undergoes reduction.
oxidation half reation Reduction half reaction
Fe ------------------- Fe+3 H+ ----------------- H2
Fe ---------------- Fe+3 + 3e- 2 H+ + 2e- -------------- H2
3)mass of Fe=25,3 grams
molar mass of Fe= 55.85 gram/mole
number of moles of Iron= 25.3/55.85 =0.453 moles
mass of H2SO4 = 65.8 grams
molar mass of H2SO4 = 98.0grams
number of moles of H2SO4 = 65.8/98=0.671 moles
according to eqaution
2 moles of Iron = 3 moles of H2SO4
0.453 moles of Iron= ?
= 0.453x3/2= 0.6795 moles of H2SO4
number ofmoels of H2SO4 = 0.6795 moles
we need 0.6795 moles of H2SO4 .we have 0.671 moles of H2SO4. so it is limiting reagent
according to equation
3 moles of H2SO4 = 3 moles of H2
0.671 moles of H2SO4 = 0,671x3/3= 0.671 moles of H2
number of moles of H2 = 0.671 moles
molar mass of H2 = 2.0grams
mass of 0.671 moles = 2.0x0.671= 1.342 grams
mass of H2 produced= 1.342 grams.
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