gibbs free energy of formation is 25.1 kj/mole for question 65 (i) ???,??-150.0

Question

gibbs free energy of formation is 25.1 kj/mole for question 65

(i) ???,??-150.0 mbar (ii) RHOH 100.0 mbar (iii) PCH,OH 10.0 mbar c. Explain why methanol spontaneously evaporates in open air at 250°C. es Consider the reaction: CH OH(g)COg) + 2 H2(8) to Calculate ?,G for this reaction at 125°C under the following conditions: at ????? 0.855 bar Pco 0.125 bar es om to = 0.183 bar 66. Consider the reaction: co2(g) + CC14(g)--2 COCI2(g) lict hat Calculate A,G for this reaction at 125 °C under the following conditions: Peo, 0.112 bar

Explanation / Answer

Free energy change of a reaction under non-standard conditions is given by

dGrxn= dGorxn + RTlnK

Given that,

dGorxn = 25.1 KJ/mol

R = 8.314 J/mol.K

T = 25 + 273 = 298 K

K = [CO][H2]^2/[CH3OH] = (0.125)(0.183)^2/(0.855) = 0.0049

dGrxn = 25.1 KJ/mol+((8.314*10^-3KJ/mol.K)(298 K)ln(0.0049)) = 11.9 KJ/mol

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