Note: It is recommended that you save your response as you complete each questio

Question

Note: It is recommended that you save your response as you complete each question. Question 1 (2 points) A battery is made using Sn/Sn2+ and Fe/Fe2+ half-cells. The standard reduction potential of Sn2+ is-0.14 V, and the standard reduction potential of Fe2+ is -0.44 V (see Table 1 in the lab). Which half-cell should be connected to the postive terminal of the voltmeter? tin, and this will be the anode. tin, and this will be the cathode. iron, and this will be the anode. iron, and this will be the cathode. Save

Explanation / Answer

here in the above question we have Fe/Fe2+ and Sn/Sn2+

the reduction potential of Fe2+ = -0.44 V

the redution potential of Sn2+ = -0.14 V

here we see that the reduction of Sn2+ is easy as compare to Fe2+ .we have to apply 0.14 V in opposite direction in case of Sn . whereas 0.44 V in case of iron . so Sn will reduce

now reduction will take place at cathode .

so correct option is B

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