Explain the difference in the bond dissociation energies for the following bonds

Question

Explain the difference in the bond dissociation energies for the following bonds: (C?F, 450 kJ/mol), (N?F, 270 kJ/mol), (O?F, 180 kJ/mol), (F?F, 159 kJ/mol).

Explain Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. Reset Help The electronegativity difference between elements for C- F is N-F is , for 0.5 1.0 1.5 for O- F is for F F is bond polarity leads to increased 2.5 bond strength. 3.0 Increased Decreased

Explanation / Answer

The energy that is required to dissociate the bond is known as bond dissociation energy. The stronger the bond has higher bond dissociation energy. This order of bond dissociation energy can be explained on the basis of bond polarity i.e. the electronegativity difference. Higher the electronegativity difference has higher bond dissociation energy.

The electronegativity values of the given atoms are as follows:

C = 2.5, F= 4.0; N= 3.0; O= 3.5

The electronegativity difference between C-F =1.5, for N-F is 1.0, for O-F is 0.5, for F-F is 0. Increased bond polarity leads to increased bond strength.

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