At a certain temperature, the equilibrium constant K for the following reaction

Question

At a certain temperature, the equilibrium constant K for the following reaction is 0.0040: Br2(8) +OCI2(8)BrOCl(g) + BrCl(g) Use this information to complete the following table. %10 Suppose a 45. L reaction vessel is filled with 0.26 mol of Br2 and 0.26 mol of OCIl2. What can you say about the composition of the mixture in the vessel at equilibrium? There O There will be very little BroCI and BrCi. O Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits.

Explanation / Answer

Br2(g) + OCl2(g) ------> BrOCl(g) + BrCl(g)

Equilibrium constant = 0.0040

(i) There will be very little BrOCl and BrCl

This is because equilibrium constant is very small so only reactants are higher in concentration at equilibrium.

(ii) BrOCl(g) + BrCl(g) ----> Br2(g) + OCl2(g)

K=(1/0.0040) = 250

Reversing the reaction will change the equilibrium constant as reciprocal of initial equilibrium constant.

(iii) 2Br2(g) + 2OCl2(g) ------> 2BrOCl(g) + 2BrCl(g)

K=(0.0040)2 = 1.6*10-5

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