m keAss ldnitydonocatoriasignment takestakeAssignmentsessorLocatoraass nment tak

Question

m keAss ldnitydonocatoriasignment takestakeAssignmentsessorLocatoraass nment take Use the Refereaces to access important values if weeded for this question. For the following reaction, 28.7 grams of sulfar dioside are allownd to react with 6,02 grams of oxygen gas For the following r sulfur dioxide(g) + oxygen(g)-? sulfur trioide(g) What is the maximum mass of sulfur trioxide that can be formed? What is the FORMULA for the limiting reagent? grams What mass of the excess reagent remains after the reaction is complete? grams Submit Answer Retry Entire Group 8 more group attempts remaining req 2req 2req to

Explanation / Answer

1)

Molar mass of SO2,
MM = 1*MM(S) + 2*MM(O)
= 1*32.07 + 2*16.0
= 64.07 g/mol


mass(SO2)= 28.7 g

use:
number of mol of SO2,
n = mass of SO2/molar mass of SO2
=(28.7 g)/(64.07 g/mol)
= 0.4479 mol

Molar mass of O2 = 32 g/mol


mass(O2)= 6.02 g

use:
number of mol of O2,
n = mass of O2/molar mass of O2
=(6.02 g)/(32 g/mol)
= 0.1881 mol
Balanced chemical equation is:
2 SO2 + O2 ---> 2 SO3


2 mol of SO2 reacts with 1 mol of O2
for 0.4479 mol of SO2, 0.224 mol of O2 is required
But we have 0.1881 mol of O2

so, O2 is limiting reagent
we will use O2 in further calculation


Molar mass of SO3,
MM = 1*MM(S) + 3*MM(O)
= 1*32.07 + 3*16.0
= 80.07 g/mol

According to balanced equation
mol of SO3 formed = (2/1)* moles of O2
= (2/1)*0.1881
= 0.3762 mol


use:
mass of SO3 = number of mol * molar mass
= 0.3762*80.07
= 30.13 g

Answer: 30.1 g

2)
Answer: O2

3)
According to balanced equation
mol of SO2 reacted = (2/1)* moles of O2
= (2/1)*0.1881
= 0.3762 mol
mol of SO2 remaining = mol initially present - mol reacted
mol of SO2 remaining = 0.4479 - 0.3762
mol of SO2 remaining = 7.17*10^-2 mol


Molar mass of SO2,
MM = 1*MM(S) + 2*MM(O)
= 1*32.07 + 2*16.0
= 64.07 g/mol

use:
mass of SO2,
m = number of mol * molar mass
= 7.17*10^-2 mol * 64.07 g/mol
= 4.594 g
Answer: 4.59 g

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.