1.) A mixture of neon and helium gases is maintained in a 5.28 L flask at a pres

Question

1.)

A mixture of neon and helium gases is maintained in a 5.28 L flask at a pressure of 3.49 atm and a temperature of 63 °C. If the gas mixture contains 4.98 grams of neon, the number of grams of helium in the mixture is _____________g.

2.)
The stopcock connecting a 3.19 L bulb containing argon gas at a pressure of 2.96 atm, and a 4.56 L bulb containing carbon dioxide gas at a pressure of 1.69 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, the final pressure in the system is _________atm.

3.)
The stopcock connecting a 3.19 L bulb containing argon gas at a pressure of 2.96 atm, and a 4.56 L bulb containing carbon dioxide gas at a pressure of 1.69 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, the final pressure in the system is ________atm.

4.)

A 1.75 mol sample of Xe gas is confined in a 42.4 liter container at 22.6 °C.

If the temperature of the gas sample is decreased to 4.90 °C, holding the volume constant, the pressure will decrease because:

Choose all that apply.

a.) As the average speed increases, the number of molecule-wall collisions decreases.

b.) With higher average speeds, the molecules hit the walls of the container more often.

c.) With lower average speeds, on average the molecules hit the walls of the container with less force.

d.)At lower temperatures molecules have lower average speeds.

e.) None of the Above

Explanation / Answer

1)
step 1: find the total mol of gas
Given:
P = 3.49 atm
V = 5.28 L
T = 63.0 oC
= (63.0+273) K
= 336 K

find number of moles using:
P * V = n*R*T
3.49 atm * 5.28 L = n * 0.08206 atm.L/mol.K * 336 K
n = 0.6683 mol
this is total number of mol of gas

step 2: find the number of mol of Ne

Molar mass of Ne = 20.18 g/mol


mass(Ne)= 4.98 g

use:
number of mol of Ne,
n = mass of Ne/molar mass of Ne
=(4.98 g)/(20.18 g/mol)
= 0.2468 mol

step 3: find the number of mol of He
number of mol of He = total mol - number of mol of Ne
= 0.6683 mol - 0.2468 mol
= 0.4215 mol

step 4: find the mass of He

Molar mass of He = 4.003 g/mol

use:
mass of He,
m = number of mol * molar mass
= 0.4215 mol * 4.003 g/mol
= 1.69 g
Answer: 1.69 g

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