So I performed a GC experiment on Monday and I collected the data that I needed
ID: 1039659 • Letter: S
Question
So I performed a GC experiment on Monday and I collected the data that I needed to do my calculations, however, the equation that my professor gave us is complicating things, I can't seem to figure out what he wants us to put as the dilution factor ? (See pics below). If I could get some assistance with this, it would be VERY much appreciated! Thanks in advance! The areas that I highlighted are the information that I think might help you guys have a better understanding of what I should
do.
imo tater 2: 5002 ?.Explanation / Answer
You have taken 50 mg of Thymol.
Step no. 5:
Here 50 mg Thymol is dissolved into 100 mL of methanol. The concentration of the solution (T) is 50 mg/ 100 mL = 0.5 mg/ mL
Step no. 6:
10 mL of the above solution is diluted to 25 mL
The concentration of the diluted solution (T 10) = (10 mL * 0.5 mg/ mL)/ 25 mL = 0.2 mg/ ml
Step no. 7:
5 mL of the above solution is diluted to 25 mL
The concentration of the diluted solution (T 5) = (5 mL * 0.2 mg/ mL)/ 25 mL = 0.04 mg/ ml
Step no. 8:
2 mL of the above solution is diluted to 25 mL
The concentration of the diluted solution (T 2) = (2 mL * 0.04 mg/ mL)/ 25 mL = 0.0032 mg/ ml
Step 9:
1 mL of the above solution is diluted to 25 mL
The concentration of the diluted solution (T 1) = (2 mL * 0.04 mg/ mL)/ 25 mL = 0.0032 mg/ ml
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