What is the charge on the transition metal in each compound or ion? a. [Cr(NHs)

Question

What is the charge on the transition metal in each compound or ion? a. [Cr(NHs) (en)l b. [Fe(CN). c. Na [Ni(CN)l d. [Mn(CO)s] 2. For the transition metals in the question above, what word would be used to name the metal according to IUPAC rules for coordination compounds? Spelling counts a. 3. d. b. C. 4. The rea ction of a transition metal complex with EDTA is a 1:1 mole ratio which means at the equivalence point Mmetal "Vmetal MEDTA"VEDTA A 0.01944M solution of EDTA was used to determine the amount of calcium in 5 the endpoint. How many milligrams of calcium were present in the hard water sample? 0.0 mL of hard water. It took 31.88mL of EDTA to reach

Explanation / Answer

[1] Your calculation are correct

[2] When metal complexes have zero or positive charge, they are named as it is (no change). But when metal complexes have negative charge metal ion end in -ate

Cr will be named as chromium

Fe will be named as Iron

Ni will be named as nickelate

Mn will be named as manganese

[3] Mmetal= MEDTA*VEDTA / Vmetal = 0.01944 M * 31.88 mL / 50.0 mL = 0.012395 M

So, 0.012395 moles of Ca are present in 1000 mL of sample.

Atomic mass of Ca = 40.078 g/mol

therefore, 0.012395 moles of Ca mass = 0.012395 mol * 40.078 g/mol = 0.49676 g of Ca

Since, 0.49676 g of Ca is present in 1000 mL of sample

Thus, amount of Ca in 50.0 mL of sample = 0.49676 g *50 mL / 1000 mL = 0.024838 g

So, milligram of Ca in 50.0 mL of hard water sample = 24.838 mg

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