The behaviors of four different solutes when dissolved irn water are indicated b

Question

The behaviors of four different solutes when dissolved irn water are indicated by the four equations below. Match each of the resulting solutions to its expected behavior in a conductance apparatus like the one shown to the left, if the solute is present at a concentration of 0.2 M. Battery Would produce a bright light. Would produce a di Would not cause the bulb to light. Anode Cathode m light. (positive electrode) (negative electrode) HC9HO4(a) H20(eH30 (a) C9H04 (aq) HBr(g) + H20()O (a)Br (aq) KBr(s) y Kt (aq) +Br (aq) CH3OH(e)CH3 OH(aq)

Explanation / Answer

Of the four solutions, HBr and KBr are strong electrolytes, which dissociate completely into its ions. For conduction of electricity ions are neecssary. So these two would produce bright light.

A weak electrolyted such as HC9H7O4 will dissoviate only to small extent, so low concentration of ions in solution would produce a dim light.

A non-electrolyte CH3OH would not have any ion to conduct electricity and thus will not light a bulb.

HBr(g) + H2O(l) --> H3O+(aq) + Br-(aq) : would produce a bright light

KBr(s) --> K+(aq) + Br-(aq) : would produce a bright light

HC9H7O4(aq) + H2O <==> H3O+(aq) + C9H7O4-(aq) : would produce a dim light

CH3OH(l) --> CH3OH(aq) : would not cause the bulb to light

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