whats the answer 03 Question t soim shuetle Discovery in Augunt 19115, whenthe m

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whats the answer

03 Question t soim shuetle Discovery in Augunt 19115, whenthe maximum winds of the storm were sbout 90 mite and the pressure was 400 mbar lower at the center thannenal atmaspheric preure, In contrast, the central pressure of Hunricane odrew was 200 mbar lower tha suroundings whee it ht souts Florida with winds ashigh in 165 Buy Gsods, Fual Your Flipps Movies, Muaic 7th attempt See Periodic Table See Hnt If a small weather balloon with a volume of 440L at a pressure of 1.00 atmosphere was deployed at the edge ot Typhoon Odessa (in picturel, what was the volume of the baloon when it reached the center? 031s>

Explanation / Answer

Let the temperature of the balloon be constant,

At the edge of Typhoon Odessa:

P? = 1 atm = 1013.25 mbar,

V? = 44.0 L
At the center of Typhoon Odessa:

P? = (1013.25 - 40.0) mbar = 973.25 mbar,

V? =?

Using Boyle's law ie,

P?V? = P?V?

On rearranging, we get,
V? = V? × (P?/P?)

Putting the respective values, we get

= (44.0 L) × (1013.25/973.25)

= 45.8 L

Therefore, Volume of the balloon at the center of Typhoon Odessa = 45.8 L

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