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A isothermal isoplethal isocratic isobaric adiabatic B The nicotine concentratio

ID: 1038651 • Letter: A

Question

A

isothermal

isoplethal

isocratic

isobaric

adiabatic

B

The nicotine concentrations in the phases resulting from the heating process in the Question ABOVE are approximately:

30%, 70%

24%, 51%

18%, 62%

9%, 73%

1%, 82%

C

The fractional amounts of the coexisting phases resulting from the heating process in Question ABOVE are (phase more dilute in nicotine is listed first):

0.10, 0.90

0.20, 0.80

0.40, 0.60

0.60, 0.40

0.80, 0.20

One phase ?208? 20? o 160 Two phases C 120 ! 60.8" 40 One phase 0 0 20 40 60 80 10 Nicotine in water (% by weight)

Explanation / Answer

(A)

Isobaric

(C)

Using lever rule we can find out the fractional amounts of each phase at a given point in two phase region:

ac / bc = 13/63 = 0.20

ab / bc = 50 / 63 = 0.80

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