eactant Consider a sihuation in which 136 g of Ps are exposed to 144 gof O Part
ID: 1038249 • Letter: E
Question
eactant Consider a sihuation in which 136 g of Ps are exposed to 144 gof O Part A What is the maximum number of moles of PyO, that can theoretically te made from 136 g of P, and excess onygen? Express your answer to three significant figures and incluude the appropriate units View Available Heels) 2 20 mol Correct Part What is the maximum number of males of P0, hat can thecrelicaly be de fom 144 g of s and excess phosphous? Express your answer to three signficent figures and include the appropriate usits Vew Pvailable Hintts) 1.80 mol Correet Part C Express your answer to three signficast Sgures and inclade the appropriate units View Avalable HnsExplanation / Answer
From part A
we calculated the moles of P2O5 that can form if P4 were the limiting reagent.
From part B we calculated that 1.8moles of P2O5 can be formed if O2 were the limiting reagent.
PartC
we found that O2 is the actual limiting reagent here and thus the theoretical yield of P2O5 from 144g of O2 is 1.8moles
Thus the theoretical yiled (g) of P2O5 = moles x molar mass
= 1.8molx 142g/mol
=255.6 g
part D
It is observed that the actual yield in the reaction is 194g of P2O5 .
% yield = actual yield x 100/ theoretical yield
= 194g x100 / 255.6
= 75.89%
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