how can I solve this question in a response that is at least 250 words in length
ID: 1038134 • Letter: H
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how can I solve this question in a response that is at least 250 words in length?
item.id 7036320 3-Sp18A um Written Assignment 2 - Oxidation Numbers Problem 8.51 part B in the Mastering Chemistry homework set for chapter 8 asks 'Assign axidation numbers to each of the atoms O, C. S in OCS Chapter 4 section 4 of the textbook outlines the rules for assigning oxidation numbers to atoms in a answer that The Mastering Chemistry homework is O is-2. C is +2, and S is 0 (remember this when to the look up the answer to problem 8.51 in the back of the textbook it will say that the answer is O is-2 C is .4, and S is-2. Additionally, if you google oxidation numbers for OCS you will find multiple sites also stating the answer is 0 is-2. ? is +4, and S is-2. Explain why the correct answer from Mastering is O is -2. C is +2 and S is O using the y from chapters 7 and 8 Use the rubric to guide your response Crit and correct gra ot OCS are O is 2. Cn 2 and SisExplanation / Answer
OCS is a triatomic molecules with C as a central atom.
If we look up oxidation numbers of each atoms
1) Oxidation number of Oxygen
We know the electronic configuration of it. 1s22s22p4.
it rerequires 2 electrons to attain octet configuration. Here it is bonded to carbon atom whose electronegativity is less than it. So it takes up 2 electrons and becomes O2-. Oxidation number is tendency to give or gain electrons. Hence Oxygen is gaining two electrons from carbon so it's oxidation number is -2
2) oxidation number of sulphur
It's configuration is 1s2 2s22p63s23p4 . It requires 2 electrons tto reach Ar configuration. It takes up two electrons from carbon, as it is more elelectro negative than carbon and becomes S2-. So its oxidation number is -2.
3) Oxidation number of Carbon. It's configuration is 1s2 2s22p2. Here it is already given its four electrons to oxygen and sulphur ( 2 to oxygen and 2 to sulphur). Reached helium configuration and stabilised. So its oxidation number is +4.
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