may i ask how to calculate the percent error? thanks tion 1 Reaction 2 Reaction

Question

may i ask how to calculate the percent error?   thanks

tion 1 Reaction 2 Reaction 3 ENTHALPY OF REACTION for THREE REACTIONS Record Mand V 1. Mass of solid NaOH(g) 2. Mass of total solution (g) 3. Initial temperature C) 4. Final temperature C) 7.7 5. Change in temperature, AT (C) 6. Heat gained by solution, q (kJ) 7. Moles of NaOH consumed (mol) le 4 (e Enthalpy ofreaction, ?H (kJ/mol) ? ??, HESSES LAW CALCULATION FOR REACTION 2: nLe Accepted Value for ??, [# 8] 10, Experimental Value for ?????,+?? 11. Percent Error

Explanation / Answer

accepted value = -82 KJ/mol

experimental value = -118 KJ/mol

Step 1: Subtract the accepted value from the experimental value

i.e., 118-82 = 36 KJ/mol

Step 2: Divide that answer by the accepted value

i.e., 36/82 = 0.439

Step 3: Multiply that answer by 100 and add the % symbol to express the answer as a percentage

I.e., 0.439* 100 = 43.9%

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