ople Window Help 2 1 Online teaching and xThermodynamic Data nt/takeCovalentActi
ID: 1037864 • Letter: O
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ople Window Help 2 1 Online teaching and xThermodynamic Data nt/takeCovalentActivity.do?locator assignment-take&takeAssignmentSessionLocator; assignment ×Yaconsider TheReaction 2H25(X April 3rd Eng 48 minutes ag Use the References to access importast values if needed for this question Hist Quiz on s 48 minutes ag For the reaction AH -1036.0 kJ and AS -152.9 J/K The standard free energy change for the reaction of 1.99 moles of H.S(g) at 292 K, 1 atm would be This reaction is (reactant, product) Assume that ??° and ? So are independent of temperature. kJ favored under standard conditions at 292 K Submit Answer Retry Entire Group 9 more group attempts remaining NextExplanation / Answer
The standard free energy change for a reaction is defined by the formula
?G0 = ?H0 ? T?S0
Given that ?H0 = -1036.0 KJ, ?S0 = -152.9 J/K and T= 292 K
Substituting these values in the above equation, we get:
?G0 = -1036.0 KJ- 292* (-152.9 J/K) = (-1036.0 + 44.65) KJ = - 991.4 KJ
The standard gibbs free energ change is defined for 1 mol of a substance. So for 1.99 moles of H2S the standard gibbs free energ change would be
?G0 = 1.99 moles * (- 991.4 KJ / 1 mol) = -1972.8 KJ
The reaction is product favored at standard conditions at 292 K because ?G0 is negative and the reaction would be spontanneous.
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