About 88 g of sodium nitrate (NaN or unsaturated? What would happen if you added
ID: 1037486 • Letter: A
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About 88 g of sodium nitrate (NaN or unsaturated? What would happen if you added ten more grams of sodium nitrate to the solution? What would happen if you added the ten grams and raised the temperature to 40°c? Os) dissolves in 100 g of water at 20°C. Is this solution saturated a. This solution is unsaturated. Adding ten additional grams of solute (NaNO3) would result in a homogeneous solution. Raising the temperature of the solution by 20°C would not affect the solution containing the ten additional grams of solute other than enabling the solution to carry additional grams of solute. b. According to Figure 14.1, the NaNO, solution prepared above would be saturated. Adding ten lute (NaNO 3) woul d result in the excess solute precipitating out of the solution and collecting as a solid on the bottom of the container in which it was prepared Subjecting the saturated NaNOs solution to a twenty degree C temperature increase would result in the excess, solid solute dissolving. The solution of 98 g NaNOs in 100 g of water at 40°C would become unsaturated This solution is unsaturated. The addition of ten more grams of solute would result in a saturated solution. Increasing the temperature to 40°C would result in an unsaturated solution. This solution is saturated. Adding 10 g of solute to the already saturated solution would make the solution supersaturated. Increasing the temperature to 40°C would result of the solid solute dissolving. However, some of the solid solute would remain on the bottom of the container in which it was prepared. c. d. in someExplanation / Answer
3) The solubility curve of NaNO3 was required, which you haven’t provided unfortunately. However, I have taken help of the solubility curve obtained from a text book.
We added 88 g solid NaNO3 to 100 g of water at 20°C. As per the solubility curve of NaNO3, the solubility of NaNO3 is at about 88g/100 g water at 20°C. Therefore, the added NaNO3 will dissolve completely to form a saturated solution. A saturated solution is a solution which contains the maximum amount of solute dissolved in a given amount of a solvent at a particular temperature.
When 10 g of excess NaNO3 is added to this solution, the solution is supersaturated. A supersaturated solution contains excess solute (more solute than a saturated solution) and the excess solute remains undissolved in the solvent at the given temperature. However, increasing the temperature of the solution causes some of the excess solute to dissolve in the solution; however, still a portion of the solute will remain undissolved and remain at the bottom of the container.
Therefore, (d) is the correct answer.
4) A strong electrolyte is defined as one which dissociates completely into ions in an aqueous solution. These ions are free to move in the solution and the movement of the ions conduct electric current. Usually ionic compounds dissociate completely into oppositely charged ions and these ions carry electric current. Therefore, (b) is the correct statement.
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