Unknown sample no. Trial I Trial 2 1. Mass of sample (g) 2 Mass of generator + 3
ID: 1037251 • Letter: U
Question
Unknown sample no. Trial I Trial 2 1. Mass of sample (g) 2 Mass of generator + 3. Instructor's approval of apparatus C. Determination of Volume, Temperature, and Pressure of the Carbon Dioxide Gas 1. Initial reading of volume of water in CO-collecting 2244 1g 2ex sample before reaction (g) graduated cylinder (mL) 2 Final reading of volume of water in CO-collecting graduated cylinder (mL) 3. Volume of CO,(g) collected (L) 4. Temperature of water (C) 5. Barometric pressure (torr) 6. Vapor pressure of H,O atC (torr) 7. Pressure of dry CO,(g) (torr) D. Amount of Carbon Dioxide Gas Evolved 210 C 21° ? 18 0 Ble 150.0 1504 1. Mass of generator + sample after reaction (g) 2. Mass loss of generator = mass CO2 evolved (g) 3. Moles of CO, evolved (mol) 0,069 o.ous 0, 0013 0,04 0.050y4.01 0.00134) mdl (2 003g/4.01g-0. 0 u31 mol (02 Experiment 13 18 110Explanation / Answer
Molar volume of CO2 in trial 1 = 23 L / 0.0013 mol
= 17692.30 L/mol
Molar volume of CO2 in trial 1 = 24 L / 0.0014 mol
= 17142.85 L/mol
Average molar volume = 17417.58 L/mol
CaCO3 = CO2 + CaO
Moles of CaCO3 in trial 1 = 0.0013 mol
Moles of CaCO3 in trial 2 = 0.0014 mol
Mass of CaCO3 in trial 1 = 0.0013 mol x 100 g/mol
= 0.13 g
Mass of CaCO3 in trial 2 = 0.0014 mol x 100 g/mol
= 0.14 g
Mass of original sample in trial 1 = 0.238 g
Mass of original sample in trial 2 = 0.248 g
% CaCO3 in trial 1 = 0.13*100/0.238 = 54.62%
% CaCO3 in trial 2 = 0.14*100/0.248 = 56.45%
Average percent of CaCO3 = 55.535%
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.