XGAn electrolyte is a substano urse Home post-lecture Post Lecture Homework Chap

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XGAn electrolyte is a substano urse Home post-lecture Post Lecture Homework Chapter 09- Microsoft Edge 96659723 com/myctjitemView? post-lecture: Post Lecture Homework Chapter 09 Problem 9.46 0 600 mole glucose in 0.150 L of a glucose solution Express your answer with the appropriate units Constants 1 Periodic Table Calculate the molarity of the following solutions Molarity- Value Submit Reauest Answer - Part B 69 0 g of HC in 2 00 L of a HCI solution Express your answer with the appropriate units. Molarity Subinit ?Type here to ?

Explanation / Answer

A)

Molar mass of C6H12O6,

MM = 6*MM(C) + 12*MM(H) + 6*MM(O)

= 6*12.01 + 12*1.008 + 6*16.0

= 180.156 g/mol

mass(C6H12O6)= 0.600 g

use:

number of mol of C6H12O6,

n = mass of C6H12O6/molar mass of C6H12O6

=(0.6 g)/(180.156 g/mol)

= 3.33*10^-3 mol

volume , V = 0.150 L

use:

Molarity,

M = number of mol / volume in L

= 3.33*10^-3/0.15

= 2.22*10^-2 M

Answer: 2.22*10^-2 M

B)

Molar mass of HCl,

MM = 1*MM(H) + 1*MM(Cl)

= 1*1.008 + 1*35.45

= 36.458 g/mol

mass(HCl)= 69.0 g

use:

number of mol of HCl,

n = mass of HCl/molar mass of HCl

=(69.0 g)/(36.458 g/mol)

= 1.893 mol

volume , V = 22.00 L

use:

Molarity,

M = number of mol / volume in L

= 1.893/22

= 8.603*10^-2 M

Answer: 8.60*10^-2 M

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