Objective Knowledge Check Question At a certain temperature, the equilibrium con

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Objective Knowledge Check Question At a certain temperature, the equilibrium constant K for the following reaction is 773.: Use this information to complete the following table. Suppose a 33. L reaction vessel is filled with 1.5 mol of HI. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little H2 and I2. There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 2 Hg)H29)+I2(9) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 3 H2(9)+3129)6HI(g) I Don't Know Submit

Explanation / Answer

H2(g) + I2(g) <----> 2 HI(g) ; Kc = 773

From the given data we havw only HI initially then,

                      H2(g) + I2(g) <-----> 2 HI(g) ;

initially        0        0             1.5/33L = 0.0454

change          +x       +x            -2x

equilibrium   x         x            (0.0454 - 2x)

Kc = [HI]^2/[H2][I2]

773 = (0.0454-2x)^2/(x*x)

x = 1.523 * 10^-3 = [H2] = [I2]

[HI] = (0.0454 - (1.523 * 10^-3)) = 0.0439

so there will be little amount of H2 and I2 are there.

For the reaction,

H2(g) + I2(g) <-----> 2HI(g) ; K1 = 773

for,

2HI(g) <-----> H2(g) + I2(g) ; K2 = 1/K1 = 1/773 = 1.29 * 10^-3

for the rection,

3 H2(g) + 3 I2(g) <----> 6 HI(g) ; K3 = 3 * K1 = 3 * 773 = 2319

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