glinienota kecovalentActivity.do ? locatoreas ( 90%-... | a Search m Review Topi
ID: 1035720 • Letter: G
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glinienota kecovalentActivity.do ? locatoreas ( 90%-... | a Search m Review Topios] References Use the References to access important valnes if needed for this Consider the following reaction where Ke77.5 at 600 K A reaction mixture was found to contain 2.55*10-2 moles of CO(g) 4.23 102 moles of Cl2(8) and 0.122 moles of COCh(g), in a 1.00 liter container 2.55 Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qes equals re A. must run in the forward dire B. must run in the reverse direction to reach equilibrium. C. is at equilibrium ach equilibrium ntire Group more grouExplanation / Answer
From the stoichiometric equation we can say
28 grams of CO reacts with 71 grams of Cl2 and produce 99 grams of COCl2 .
Given moles for COis 2.55×10-2. So weight is calculated by
Moles = weight/ molecular weight
I.e. Weight = 2.55×10-2× 28 = 0.74 grams
Similarly
Given moles for Cl2is 4.23×10-2
Weight = 4.23×10-2× 71.5 = 3.02 grams
For COCl2
weight = 0.122×99 = 12.078 grams
Checking equilibrium status of CO w.r.t. COCl2
99 grams of COCl2 should contain 28 grams of CO
12.078 grams of COCl2 contains how much CO
= (12.078×28)/99 = 3.416 grams.
The amount should be 3.416 grams but as per our given value it is 0.74 grams . The reaction not in equilibrium w.r.t. CO. Hence in order to be the reaction in equilibrium state, it shifts towards reactant side ( back ward).
Similarly,
Checking the equilibrium status w.r.t. Co2
99 grams of COCl2 should contain 71 grams of Cl2
12.078 grams of COCl2 contains how much Cl2
= (12.078×71)/99 = 8.662 grams.
The amount of Cl2 should be 8.662 grams but as per the calculation we have got 3.02 grams. So w.r.t Cl2 reaction shits towards left side.
The Reaction Quotient = 0.122/(2.55×10-2× 4.23×10-2) = 116.19.
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