ill Verizon 5:22 PM * 59% a session.masteringchemistry.com C Quiz 4 Item 9 9of 1

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ill Verizon 5:22 PM * 59% a session.masteringchemistry.com C Quiz 4 Item 9 9of 12 The complete combustion of octane, CHis, a component of gasoline, proceeds as follows: 2CsHis(1) +2502(g)-+16CO2(g) +18H2O(g) You may want to reference (Pages 102-105) Section 3.6 while completing this problem. - Part A How many moles of O2 are needed to burn 1.55 mol of CsH1s? Express the amount in moles to three significant digits. n 194 mo Correct When converting between moles based on a reaction, you use the coefficients of the balanced chemical equation. You should always include the units in such conversions to ensure that the appropriate units cancel. The units of mol CsH1s cancel because it occurs once in both the numerator and denominator 25 mol O2 Part B How many grams of O2 are needed to burn 14.0 g of CH18? Express the mass in grams to three significant digits. m 93.3 X Incorrect: Try Again; S attempts remaining -Part C Octane has a density of 0.692 g/mL at 20 C. How many grams of O2 are required to burr 15.0 gal of CsHis? Express the mass in grams to three significant digits.

Explanation / Answer

Part B

One mole of octane requires (25/2) 12.5 moles of oxygen.

Moleculare weight of octane = 114 g/mol

moles of octane to be burned = 14/114 = 0.122 moles

Therefore, moles oxygen required = 0.122*12.5 = 1.53 moles

molecular weight of oxygen = 16 g/mol

mass of oxygen = 1.53*16 = 24.56 grams

Part C

15 gallon of octane = 56781 ml

mass of octane to be burned = 0.692*56781 = 39292.4 g

moles of octane to be burned = 39292.4/114 = 344.67 moles

Therefore, moles oxygen required = 344.67*12.5 = 4308.3 moles

molecular weight of oxygen = 16 g/mol

mass of oxygen = 4308.3*16 = 68934.1 grams

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