Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Nut Marshmallow Other Food Mass of the water 50g 50g 50g Food Item Description:

ID: 1035600 • Letter: N

Question

Nut

Marshmallow

Other Food

Mass of the water

50g

50g

50g

Food Item Description:

Nut (Type:Almond)

Marshmallow (Jumbo)

Other Sample (French Fry)

Mass of food, cup, and clamp – initial

29.4g

35.7g

29.6g

Mass of food, cup, and clamp – final

29.3g

35.0g

29.5g

Mass of burned food

0.1g

0.7g

0.1g

Observations of the Flame (intensity, length of time burning, etc.)

Intensity was low and burning was quick reacting as well as quick lived

Intensity of flame very high burned for half minute

When flame occurred, it was high intensity burning was sporadic and short

Water temp – initial (°C)

20 C

20 C

23 C

Water temp – final (°C)

22.0 C

33 C

23.5 C

Change in temp (?T) (°C)

2.0 C

13 C

0.5 C

(Q) Energy Released (kcal/g)

Energy Estimated on Package (kcal/g)

Percent Difference

Determination of Calories according to Atwater Factors (kcal/g)

Pleae show work can I can walk through this

Nut

Marshmallow

Other Food

Mass of the water

50g

50g

50g

Explanation / Answer

specific heat of water = 1 cal/g.oC

For nut,

Total mass = 50 + 0.1 g = 50.1 g

dT = 2 oC

Q = mCpdT = 50.1 x 1 x 2/1000 = 0.1002 kcal

Percent difference = 0.1002 x 100/0.78435 = 12.8%

Calories kcal/g = 0.1002 kcal/0.1 g = 1.002 kcal/g

For marshmallow,

Total mass = 50 + 0.7 g = 50.7 g

dT = 13 oC

Q = mCpdT = 50.7 x 1 x 13/1000 = 0.6591 kcal

percent difference = 0.6591 x 100/0.78435 = 84.03%

Calories kcal/g = 0.6591 kcal/0.7 g = 0.94 kcal/g

For other food,

Total mass = 50 + 0.1 g = 50.1 g

dT = 0.5 oC

Q = mCpdT = 50.1 x 1 x 0.5/1000 = 0.02505 kcal

percent difference = 0.02505 x 100/0.78435 = 3.17%

Calories kcal/g = 0.02505 kcal/0.1 g = 0.25 kcal/g