Need help with Part C below only. Thank You:) Part B A solution is composed of 1

Question

Need help with Part C below only. Thank You:)

Part B A solution is composed of 1.90 mol cyclohexane (P= 97.6 torr) and 2.20 mol acetone ( Pac 229.5 torr). What is the total vapor pressure Ptotal above this solution? Express your answer with the appropriate units. Hints Potal= 168 torr Submit My Answers Give Up Correct If a third volatile component had been present in this solution, the total pressure would be calculated in a similar manner but would involve three terms rather than two. For example, Part C As you saw in Part B, the vapor above the cyclohexane-acetone solution is composed of both cyclohexane vapor and acetone vapor. What mole fraction of the vapor above the solution, Xcy (vapor), is cyclohexane? Express your answer numerically.

Explanation / Answer

x1*P°1 = y1*PT

x1 = mol of cyclhexane / toal mol = 1.9/(1.90+2.20) = 0.4634

P°1 = 97.6 torr

Ptotal = 168 torr

then, substitute all

x1*P°1 = y1*PT

0.4634*97.6 = y1*168

y1 = 0.4634*97.6/168

y1 = 0.2692, mol fraction of cyclohexane in vapor

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